Draw perpendicular bisectors of sides AB and AC such that they meet at O. Join OB.
So, O is the centre and OB is the radius of the circumcircle of △ABC.
From the above constructions, we see that the circumradius of △ABC is 2.8 cm.
Draw a triangle with two sides equal to 5 cm and 6 cm and the angle between them is 45∘. Then the circumradius of this triangle measures
Draw a triangle with two sides equal to 4 cm and 5 cm and the angle between them is 90∘. Then the circumcentre of this triangle lies on the third side.