Question

Draw a velocity-time graph for the uniformly accelerated object. Using velocity-time graph derive v=u+at.

Answer 1

Velocity-time graph for the uniformly accelerated object is given by,

We know, Acceleration is represented by the slope of the v-t curve.

Acceleration,$a=\frac{∆v}{∆t}$

Let v be final velocity and u be initial velocity.

Therefore, $a=\frac{v-u}{t-0}=\frac{v-u}{t}$

On rearranging,

$$\begin{gathered} a=\frac{v-u}{t} \\ at=v-u \\ \mathit{v}\mathbf{=}\mathit{u}\mathbf{+}\mathit{a}\mathit{t} \end{gathered}$$