Question

Draw ∆ ABC in which AB = 5.5 cm, BC = 6 cm and CA = 7 cm. Also, draw perpendicular bisector of side BC.

Answer 1

Steps of construction:

1. Draw a line segment AB of length 5.5 cm.
2. From B, cut an arc of radius 6 cm.
3. With centre A, draw an arc of radius 7 cm intersecting the previously drawn arc at say, C.
4. Join AC and BC to obtain the desired triangle.
5. With centre B and radius more than $\frac{1}{2}BC$, draw two arcs on both sides of BC.
6. With centre C and the same radius as in the previous step, draw two arcs intersecting the arcs drawn in the previous step at X and Y.
7. Join XY to get the perpendicular bisector of BC.