Question 78

Draw all the diagonals of a pentagon ABCDE and name them.

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Solution

Since, a pentagon has five sides, i.e. n = 5

Hence, the number of diagonals = $\frac{5 (5 - 3)}{2} = 5$

The diagonals of pentagon are AC, AD, BE, BD and CE.

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Question 78 Draw all the diagonals of a pentagon ABCDE and name them.

Since, a pentagon has five sides, i.e. n = 5 Hence, the number of diagonals = 5(5−3)2=5 The diagonals of pentagon are AC, AD, BE, BD and CE.

Question 78

Draw all the diagonals of a pentagon ABCDE and name them.

Since, a pentagon has five sides, i.e. n = 5

Hence, the number of diagonals = $\frac{5 (5 - 3)}{2} = 5$

The diagonals of pentagon are AC, AD, BE, BD and CE.