Draw an angle $125^{\circ}$ and take point A on one of its arm and B on the second arm such that OA = OB. Draw the perpendicular bisector of OA and OB. [4 MARKS]

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Solution

Construction of angle: 1 Mark
Construction of bisector: 1 Mark
Steps: 2 Marks

i) Draw any angle $125^{\circ}$ with O as its centre.
ii) Take points A and B on its two arms. Now taking O and A as centre and radius more than half of AB draw arcs at C and D.
iii) Similarly, draw the arcs at E and F on side OB.
iv) Join CD and EF.

These are the perpendicular bisectors of OA and OB.

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Q. Two fixed points

A

and

B

are taken on the axes such that

O A = a

and

O B = b

; two variable points

A^{^{'}}

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B^{^{'}}

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A B^{^{'}}

and

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,
and (2) when

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In the figure shown, the arms of angle AOB is/are

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Draw an angle 125∘ and take point A on one of its arm and B on the second arm such that OA = OB. Draw the perpendicular bisector of OA and OB. [4 MARKS]

Draw an angle $125^{\circ}$ and take point A on one of its arm and B on the second arm such that OA = OB. Draw the perpendicular bisector of OA and OB. [4 MARKS]