Draw an angle of 80∘ with the help of protractor. Then, construct angles of
(i) 40∘
(ii) 160∘
(iii) 120∘
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Solution
First, draw an angle of 80∘ say ∠QOA=80∘ with the help of protractor. Now, use the following steps to construct angles of
(i) 40∘
(ii) 160∘
(iii) 120∘
(i) Taking O as the centre and any radius draw an arc which intersects OA at E and OQ at F.
(ii) Taking E and F as the centres and radius more than 12 EF draw arcs which intersect each other at P.
(iii) Join OP, thus, ∠POA=40∘[∵40∘=12×80∘]
(iv) Now, taking F as the centre and radius equal to EF draw an arc which intersects the arc drawn in step (i) at S.
(v) Join OS, thus, ∠SOA=160∘
(vi) Taking S and F as centre and radius more than 12SF draw arcs which intersect each other at R.(Or simply we need to bisect ∠SOF=80∘)