Draw an equilateral triangle of side 5 cm and its circumscribed circle. Find the length of the radius.
2.9 cm
Draw the perpendicular bisectors of any two sides of the triangle.
Let the perpendicular bisector of BC and AC be drawn which meet at point O.
Taking O as the centre and radius equal to OA (or OB or OC) draw the circle.
Since the triangle is equilateral the perpendicular bisector passes through the vertex.
Consider triangle OBM; OB is the circumradious
cos(30∘)=BMOB
⟹√32=2.5OB
⟹OB=5√3=2.88