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Question
Draw an equilateral triangle with length of side 6.5 cm. and let us draw a parallelogram equal in area to that triangle and having an angle 45∘.
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Solution
Steps of Construction:
1. We draw a triangle ABC of given dimensions.
2. We draw a perpendicular bisector of side AB which intersects AB at D.
3. Join C to D.
4. Draw a line parallel to AB through C by completing the parallelogram ACQB.
5. From D, construct ∠GDB=45∘.
6. The line cuts parallel line through C at E.
7. From E, cut an arc of length DB on the parallel line.
8. Mark the point as F.
9. Join F to B.
10. DBFE is the required parallelogram.
1. We draw a triangle ABC of given dimensions.
2. We draw a perpendicular bisector of side AB which intersects AB at D.
3. Join C to D.
4. Draw a line parallel to AB through C by completing the parallelogram ACQB.
5. From D, construct ∠GDB=45∘.
6. The line cuts parallel line through C at E.
7. From E, cut an arc of length DB on the parallel line.
8. Mark the point as F.
9. Join F to B.
10. DBFE is the required parallelogram.
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