Draw formulas for the first five members of each homologous series beginning with the following compounds.

$H - C O O H$

$C H_{3} C O C H_{3}$

$H - C H = C H_{2}$

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Solution

The first five members of each homologous series beginning with the given compounds are shown as follows:

$H - C O O H$ : Methanoic acid
$C H_{3} - C O O H$ : Ethanoic acid
$C H_{3} - C H_{2} - C O O H$ : Propanoic acid
$C H_{3} - C H_{2} - C H_{2} - C O O H$ : Butanoic acid
$C H_{3} - C H_{2} - C H_{2} - C H_{2} - C O O H$ : Pentanoic acid

$C H_{3} C O C H_{3}$ : Propanone $C H_{3} C O C H_{2} C H_{3}$
: Butanone
$C H_{3} C O C H_{2} C H_{2} C H_{3}$ : Pentan-2-one
$C H_{3} C O C H_{2} C H_{2} C H_{2} C H_{3}$ : Hexan-2-one
$C H_{3} C O C H_{2} C H_{2} C H_{2} C H_{2} C H_{3}$ : Heptan-2-one

$H - C H = C H_{2}$ : Ethene
$C H_{3} - C H = C H_{2}$ : Propene
$C H_{3} - C H_{2} - C H = C H_{2}$ : 1-Butene
$C H_{3} - C H_{2} - C H_{2} - C H = C H_{2}$ : 1-Pentene
$C H_{3} - C H_{2} - C H_{2} - C H_{2} - C H = C H_{2}$ : 1-Hexene

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H - C H = C H_{2}

Draw formulas for the first five members of each homologous series beginning with the following compounds. (a) H–COOH (b) CH₃COCH₃ (c) H–CH=CH₂

H - C H = C H_{2}

C H_{3} C O C H_{3}

H C O O H

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