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Draw molecula...

Question

Draw molecular orbital diagram of $O_{2}$ or $N_{2}$ with magnetic behavior and bond order.

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Solution

As it can be seen from the MOT of $O_{2}$ , The electrons in the highest occupied molecular orbital are unpaired therefore it is paramagnetic in nature. Also, the bond order can be calculated as $[N_{b} - N_{a}] / 2 = [10 - 6] / 2 = 2$ . Therefore there is a double bond present as $O = O$ .

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