Question

Draw parallelogram ABCD with the following measurements and calculate its area.
$AB=5.5cm$, $\angle$ DAB = ${50}^o$ and $BD=7cm.$

Answer 1

Area of parallelogram ABCD$=2\times ar△ABD$

$ar△ABD=\sqrt{s(s-a)(s-b)(s-c)}$

$s=\frac{a+b+c}{2}=\frac{4.5+7+9}{2}=10.75cm$

$ar△ABD=\sqrt{10.75\times 5.25\times 3.75\times 1.75}$

$=19.25c{m}^2$

$\therefore$ Area of parallelogram ABCD$=2\times 19.25=38.50c{m}^2$