Question

Draw parallelogram $ABCD$ with the following measurements and calculate its area.
$AB=6cm,BD=8cmandAD=5cm.$

Answer 1

Area of parallelogram ABCD$=2\times ar△ABC$

$ar△ABC=\sqrt{s(s-a)(s-b)(s-c)}$

$s=\frac{a+b+c}{2}=\frac{8+6+5}{2}=9.5cm$

$ar△ABC=\sqrt{9.5\times 1.5\times 3.5\times 4.5}=14.98c{m}^2$

$\approx 15c{m}^2$

Area of parallelogram ABCD$=2\times 15=30c{m}^2$