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Question

Draw parallelogram ABCD with the following measurements and calculate its area.
AB=7 cm, AC=10 cm and AOB = 100o where ¯¯¯¯¯¯¯¯AC and ¯¯¯¯¯¯¯¯¯BD intersect at O.

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Solution

Area of parallelogram ABCD=2×arABC
arABC=s(sa)(sb)(sc)
s=a+b+c2=7+6.4+102=11.7cm
arABC=11.7×4.7×5.3×1.7=22.25cm2
Area of parallelogram ABCD=2×22.25=44.50cm2

945143_617512_ans_44e5643cfc6c470eb29c38d2a8a0a85a.JPG

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