Draw ∆ PQR in which ∠Q = 80°, ∠R = 55° and QR = 4.5 cm. Draw the perpendicular bisector of side QR.

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Solution

Steps of construction:

Draw a line segment QR = 4.5 cm.

Draw $∠ R Q X = 80 ° a n d ∠ Q R Y = 55 °$ .

Let QX and RY intersect at P so that PQR is the required triangle.

With Q as centre and radius more that 2.25 cm, draw arcs on either sides of QR.

With R as centre and radius more than 2.25 cm, draw arcs intersecting the previous arcs at M and N.

Join MN; MN is the required perpendicular bisector of QR.

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∠

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∆

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70^{°}

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80^{°}

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