Draw square ABCD with side measuring 5.8 cm.

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Solution

Steps of construction :

(1) Draw a line segment AB = 5.8 cm.
(2) At A, draw $∠ X A B$ = 90° and at B, draw $∠ Y B A$ = 90° (since each angle in a square is of 90°)
(3) Taking A as centre, draw an arc of radius 5.8 cm that intersects XA at D.
(4) Taking B as centre, draw an arc of radius 5.8 cm that intersects YB at C.
(5) Join D and C.
The required square ABCD is thus drawn.

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Similar questions

5.8 c m

A B C D

A D = 4.2 c m

D C = 5.8 c m

∠ D = 43^{o}

Construct a square, each of whose diagonals measures 5.8 cm.

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