Draw the circles whose equation are
$3 x^{2} + 3 y^{2} = 4 x$ .

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Solution

The given equation of circle is $3 x^{2} + 3 y^{2} = 4 x .$

Making perfect square, the equation of circle becomes
${(x - \frac{2}{3})}^{2} + (y - 0)^{2} = {(\frac{2}{3})}^{2}$

Centre is $(\frac{2}{3}, 0)$ and radius is $\frac{2}{3}$

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Draw the circles whose equation are 3x2+3y2=4x.

The given equation of circle is 3x2+3y2=4x.Making perfect square, the equation of circle becomes(x−23)2+(y−0)2=(23)2Centre is (23,0) and radius is 23

Draw the circles whose equation are
$3 x^{2} + 3 y^{2} = 4 x$ .

The given equation of circle is $3 x^{2} + 3 y^{2} = 4 x .$

Making perfect square, the equation of circle becomes
${(x - \frac{2}{3})}^{2} + (y - 0)^{2} = {(\frac{2}{3})}^{2}$

Centre is $(\frac{2}{3}, 0)$ and radius is $\frac{2}{3}$