Question

Draw the circumcircle of $△$PMT in which PM=5.4 cm, $\angle$P = 60$°$ and $\angle$M = 70$°$.

Answer 1

Steps of construction:
1. Draw a line segment PM = 5.4 cm.
2. Draw $\angle \mathrm{MPX}=60°$.
3. Draw another angle $\angle \mathrm{PMY}=70°$. The rays PX and MY intersects at point T.
4. Then $∆$PMT is the required triangle.
5. Draw perpendicular bisectors of sides PM and PT (any two sides) which intersect at O.
6. Taking OP or OM or OT as the radius, draw the required circumcircle.