Draw the curve represented by -x-y-1

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Graphical Interpretation of Differentiability

Draw the curv...

Question

Draw the curve represented by $\sqrt{x} + \sqrt{y} = 1$

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Solution

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x = t^{2} + 1

y = 2 t + 1

x = 2 l n cot (t) + 1

y = tan (t) + cot (t)

x = \frac{2}{c o t t} + 1

y = t a n t + c o t t

x = 2 ln cot t + 1

y = tan t + cot t

\frac{d y_{1}}{d x} = \frac{x^{2} + x + 1}{y^{2} + y + 1}

\frac{d y_{2}}{d x} + \frac{y^{2} + y + 1}{x^{2} + x + 1} = 0

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