Draw the cyclic five member ring structure of furan?

Open in App

Solution

Furan is a heterocyclic organic compound, consisting of a five-membered aromatic ring with four carbon atoms and one oxygen.
Furan is aromatic because one of the lone pairs of electrons on the oxygen atom is delocalized into the ring, creating a 4n + 2 aromatic system, similar to benzene. Because of the aromaticity, the molecule is flat and lacks discrete double bonds.
The oxygen is $s p^{2}$ hybridized, leaving one lone pair in a p orbital. The lone pair in the p orbital can now contribute towards the aromaticity so that the total no of electrons in the ring is 6.

Suggest Corrections

Similar questions

Which of the following statement is correct for Buckminsterfullerene $C_{60}$ :

Which of the following monosaccharides are present as five-membered cyclic structure (furanose structure)?
(a) Ribose (b) Glucose (c) Fructose (d) Galactose

Q. Five-membered ring structures of fructose are given below. Mark the incorrect statement.

Q. Unlike most hydrocarbons, azulene (

C_{10} H_{8}

) is highly coloured (deep blue), although its isomer, naphthalene does not have significant zwitter-ionic character, azulene does.
(i) Draw a resonance structure of azulene in which five-membered ring is anionic and the seven-membered ring cationic.
(ii) Can azulene be considered aromatic?

Q. Fullerene has six membered and five membered carbon rings.

Join BYJU'S Learning Program