Question

Draw the diagram for the given information
A man sees the top of a tower in a mirror which is at a distance of $87.6m$ from the tower. The mirror is on the ground,facing upward. The man is $0.4m$. away from the mirror, and the distance of his eye level from the ground is $1.5m$ (The foot of man, the mirror and the foot of the tower lie along a straight line).

Answer 1

According to the question,

$AB=$ Height of the tower

$CD=$ Distance of the man from the mirror

$CB=$ Distance of the man from the tower

$ED=$ Distance of the eye level of the man from the ground

$△CDE\cong △ABC$ ( AA Criterion )

$\therefore \frac{CD}{CB}=\frac{ED}{AB}$

$\Rightarrow \frac{0.4}{87.6}=\frac{1.5}{AB}$

$\Rightarrow AB=\frac{\left(1.5x87.6\right)}{0.4}=328.5$ m.

$\therefore$ Height of the tower $=328.5$ m.