Question

Draw the following triangles and construct circumcircles for them.
In $△ABC,AB=6cm,BC=7cm$ and $\angle A={60}^o$

Answer 1

Given, to construct a circle for $\Delta ABC$ with the given radius $AB=6cm,BC=7cm\&\angle A={60}^o$.

Rough draft :- Ref. image

Main draft :- Ref. image

Construction steps :-

i) Draw a line segment $AB=6cm$

ii) from 'A' draw a projection of radius $\angle A={60}^o$ and mark the projection as X.

iii) Now, taking 'B' as centre draw an arc onto the projection with radius 7cm

iv) Now $\Delta ABC$ is formed.

v) Now taking a radius of more than half draw the perpendicular bisectors on either sides of the triangle and join them.

vi) The point where all the perpendicular bisectors meet, from that centre draw a circle that which touches all the vertices of the triangle.

vii) Thus, circum circle for the $\Delta ABC$ is formed.

viii) Now, name the centre of perpendicular bisectors as circum centre [S].

Conclusion :- Thus, the required circum circle for the $\Delta ABC$ is formed.