Question

Draw the geometric atomic structure of following element, showing clearly the {a} number of protons {b} number of electrons {c} number of neutrons.

${}_9{}^{}\mathrm{F}$¹⁹

Answer 1

Fluorine ${}_9{}^{}\mathrm{F}$¹⁹ — It is a chemical element with the atomic number 9

• It is the most reactive chemical element and the lightest member of the halogen element.
• It is the lightest halogen and exists in standard conditions as a highly toxic.
• The total number of electrons = atomic number.
• The total number of protons = atomic number.
• The mass number = mass of neutrons + mass of protons.
• The total number of neutron = mass number – the atomic number.

Thus, in ${}_9{}^{}\mathrm{F}$¹⁹ number of protons is 9, the number of electrons is 9, and the number of neutrons is 10, their geometric structure is as follows.