Question

Draw the geometric atomic structure of following element, showing clearly the {a} number of protons {b} number of electrons {c} number of neutrons.

${}_2{}^{}\mathrm{He}$⁴

Answer 1

Helium ${}_2{}^{}\mathrm{He}$⁴ — It is a chemical element with the atomic number 2.

• It is a noble gas.
• It is a colourless, odourless, tasteless, non-toxic, inert, monatomic gas.
• The total number of electrons = atomic number.
• The total number of protons = atomic number.
• Mass number = mass of neutrons + mass of protons.
• The total number of neutrons = mass number – the atomic number.

Thus, in ${}_2{}^{}\mathrm{He}$⁴ number of protons is 2, the number of an electron is 2, and the number of neutrons is 2, their geometric structure is as follows.