Question

Draw the graph of given equation, (i) $x+2y=10$; (ii) $2x+y+5=0$
Answer the given question.

Find 'a' if the point (-2, a) lies on the second line.

Answer 1

Given,

$x+2y=10$

$⟹y=5-\frac{x}{2}$

Substituting different values of $x$ to get corresponding values of $y$, we get

$(0,5),(2,4),(-2,6),(4,3),(-4,7)$

Plotting these points on the graph, we get the graph of the equation, $x+2y=10$

Similarly,

Given second equation,

$2x+y+5=0$

$⟹y=-5-2x$

Substituting different values of $x$ to get corresponding values of $y$, we get

$(0,-5),(1,-7),(-1,-3),(2,-9),(-2,-1)$

Plotting these points on the graph, we get the graph of the equation, $2x+y+5=0$

Corresponding y - cordinate for $x=-2$ on the second line is $-1$
So, $a=-1$