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Question

Draw the graph of given equation, (i) x+2y=10; (ii) 2x+y+5=0
Answer the given question.
Find 'a' if the point (-2, a) lies on the second line.

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Solution

Given,

x+2y=10

y=5x2

Substituting different values of x to get corresponding values of y, we get

(0,5),(2,4),(2,6),(4,3),(4,7)

Plotting these points on the graph, we get the graph of the equation, x+2y=10

Similarly,

Given second equation,

2x+y+5=0

y=52x

Substituting different values of x to get corresponding values of y, we get

(0,5),(1,7),(1,3),(2,9),(2,1)

Plotting these points on the graph, we get the graph of the equation, 2x+y+5=0

Corresponding y - cordinate for x=2 on the second line is 1
So, a=1

405425_180290_ans_b9d0e5142e6749db95fa0015b56c4cf1.png

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