Question

Draw the graph of straight line $y=-2x+3.$ Use your graph to find the area between the line and co-ordinate axes.

• A. $4.66$ sq.units
• B. $3.25$ sq.units
• C. $2.25$ sq.units
• D. $5.66$ sq.units

Answer 1

The correct option is C $2.25$ sq.units

Using graph, the point of intersection of line $y=-2x+3$
with coordinate axes are $A(0,3)$ and $B(1.5,0)$
Hence, required area of triangle $OAB$ is, $=\frac{1}{2}OA\times OB$

$=\frac{1}{2}\times 3\times 1.5$

$=\frac{9}{4}=2.25$ sq. units