Draw the graph of the cubic-polynomial f(x)=x3−2x2.
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Solution
Let y = f(x) or, y=x3−2x2. The following table gives values of y for various values of x:
x
-3
- 2
-1
0
1
2
3
4
y=x3−2x2
-45
-16
-3
0
-1
0
9
32
Thus, the curve y=x3−2x2 passes through the points (-3, -45), (-2, -16), (-1,-3), (0,0), (1, -1), (2,0), (3,9), (4,32) etc. Plotting these points on a graph paper and drawing a free hand smooth curve passing through these points, we obtain the graph of the polynomial as shown in Figure.