Question

Draw the graph of the equation $2x+3y=12$. From the graph,find the coordinates of the point:
(i) whose $y-$coordinate is $3$
(ii) Whose $x-$coordinate is $-3$

Answer 1

Given equation:$2x+3y=12$

$2x=12-3y$

$x=\frac{12-3y}{2}$

When $y=0\Rightarrow x=\frac{12-3\left(0\right)}{2}\Rightarrow \frac{12}{2}\Rightarrow x=6$

When $y=4\Rightarrow x=\frac{12-3\left(4\right)}{2}\Rightarrow x=0$

$\therefore$ The graph of the given equation is as follows:





Clearly,from the graph

(i) when $y-$coordinate is $3$, then $x-$coordinate is $\frac{3}{2}$

(ii) When $x-$ coordinate is $-3$, then $y-$coordinate is $6$.