Question

Draw the graph of the equation 3x + 5y − 15 = 0 and show that x = 1, y = 2 is not a solution of the given equation.

Answer 1

Given equation: $3x+5y-15=0$
Or, $y=\frac{15-3x}{5}$

When $x=0$, then $y=\frac{15}{5}=3$.

When $x=5$, then $y=\frac{0}{5}=0$.
Thus, we get the following table:

$\text{x}$	0	5
$y$	3	0

Plot these points $A(0,3),B(5,0)$ on the graph paper. Join the points and extend them in both the directions.
Now, from the graph we can see that $x=1,y=2$ does not lie on the line.
Moreover, we can check that $x=1,y=2$ does not satisfy the equation as well.
$LHS=3x+5y-15=3\times 1+5\times 2-15=13-15=-2$ ≠ $RHS$.
Hence, $x=1,y=2$ is not a solution of the given equation.