Question

Draw the graph of the equations $2x+3y=5$ and check whether points $(-3,4)$ and $(7,-3)$ are solution of the given equations.

Answer 1

R.E.F.Image.

Draw the graph

$2x+3y=5$

x	1	7	13
y	1	-3	-7

using this point draw a graph

let x = 1

$2\left(1\right)+3y=5$

$3y=5-2$

$3y=3$

$y=1$

let x = 7

$2\left(7\right)+3y=5$

$3y=5-14$

$3y=-9$

$y=-3$

let x = 13

$2\left(13\right)+3y=5$

$26+3y=5$

$3y=5-26$

$3y=-21$

$y=-7$

(-3, 4) & put x = -3

$2(-3)+3y=5$

$-6+3y=5$

$3y=11$

$y=\frac{11}{3}\ne 4$

so (-3, 4) is not solution.

(7,-3) put x = 7

$2\left(7\right)+3y=5$

$3y=5-14$

$3y=-9$

$y=-3$ is solution.