Question

Draw the graph of the given quadratic equation $y=(x+2)(2-x)$

Answer 1

The given quadratic equation is $y=(x+2)(2-x)$. When we substitute different values of $x$ in the equation $y=(x+2)(2-x)$ then value of $y$ changes accordingly.

When $x=0$ then

$y=(0+2)(2-0)=2\times 2=4$

The point is $(0,4)$

When $x=1$ then

$y=(1+2)(2-1)=3\times 1=3$

The point is $(1,3)$

When $x=-1$ then

$y=(-1+2)(2-(-1\left)\right)=1\times 3=3$

The point is $(-1,3)$

Hence, the coordinates are $(0,4)$, $(1,3)$ and $(-1,3)$and the graph of the quadratic equation $y=(x+2)(2-x)$ is as shown in the graph.