Question

Draw the graph of the given quadratic equation $y=x^2-8x+7$

Answer 1

The given quadratic equation is $y=x^2-8x+7$. When we substitute different values of $x$ in the equation $y=x^2-8x+7$ then value of $y$ changes accordingly.

When $x=0$ then

$y=(0{)}^2-(8\times 0)+7=0-0+7=7$

The point is $(0,7)$

When $x=1$ then

$y=(1{)}^2-(8\times 1)+7=1-8+7=0$

The point is $(1,0)$

When $x=-1$ then

$y=(-1{)}^2-(8\times -1)+7=1+8+7=16$

The point is $(-1,16)$

Hence, the coordinates are $(0,7)$, $(1,0)$ and $(-1,16)$and the graph of the quadratic equation $y=x^2-8x+7$ is as shown above.