Question

Draw the graph of the given quadratic equation $y=x^2+x-6$

Answer 1

The given quadratic equation is $y=x^2+x-6$. When we substitute different values of $x$ in the equation

$y=x^2+x-6$

then the value of $y$ changes accordingly.

When $x=0$ then

$y=(0{)}^2+0-6=0+0-6=-6$

The point is $B(0,-6)$

When $x=1$ then

$y=(1{)}^2+1-6=1+1-6=-4$

The point is $C(1,-4)$

When $x=-1$ then

$y=(-1{)}^2+(-1)-6=1-1-6=-6$

The point is $A(-1,-6)$

Hence, the coordinates are $B(0,-6)$, $C(1,-4)$ and $A(-1,-6)$and the graph of the quadratic equation $y=x^2+x-6$ is as shown in the figure.