Question

Question 3
Draw the graph of the linear equation 3x + 4y = 6.
At what points, the graph cuts x and y-axes?

Answer 1

The given equation is 3x + 4y = 6.
To draw the graph of this equation, we need atleast two points lying on the graph of,
$4y=6-3x$
$y=\frac{6-3x}{4}$

When x = 2, then
$y=\frac{6-3\times 2}{4}=\frac{6-6}{4}=0$

When x =0, then
$y=\frac{6-3\times 0}{4}=\frac{6}{4}=\frac{3}{2}$

$\begin{array}{ccc}x& 2& 0\\ y& 0& \frac{3}{2}\end{array}$

Here, we find two points $A(0,\frac{3}{2})$ and $B(2,0)$

Now, plot the points $A(0,\frac{3}{2})$ and $B(2,0)$ and join them to get the line AB.



You can seethat the graph (line AB) cuts the x-axis at the point (2, 0) and the y-axis at the point $(0,\frac{3}{2})$.