Question

Draw the graph of $(x-2{)}^2+y^2=4$ and find the co-ordinates of intersection of the circle with co-ordinate axes.

Answer 1

The graph of $(x-2{)}^2+y^2=4$ is shown in image

put $x=0$ in equation,we will get $y=0$

and if we out $y=0$ ,we will get $x=0,2$

hence $(0,0)$ and $(2,0)$ are point of intersection of curve with co-ordinate axis.