Question

Draw the graphs $EVsr$ in the following case :
A point charge $q$ is placed at the origin. How does the electric field due to the charge vary with distance $r$ from the origin?

Answer 1

We know that field is given by $\overrightarrow{E}=\frac{q}{4\pi {ϵ}_o{r}^2}\hat{r}$

Hence magnitude of field is $E=\frac{q}{4\pi {ϵ}_o{r}^2}$

Hence, $E\propto \frac{1}{r^2}$