Question

Draw the graphs of
$6-x-x^2$
and find the zeroes in each case.

Answer 1

$6-x-x^2$
When $x=-3$
$y=6-(-3)-(-3{)}^2=6+3-9=0$
When $x=-2$
$y=6-(-2)-(-2{)}^2=6+2-4=4$
When $x=-1$
$y=6-(-1)-(-1{)}^2=6+1-1=6$
When $x=0$
$y=6-0-0^2=6$
When $x=1$
$y=6-1-1^2=4$
When $x=2$
$y=6-2-2^2=4-4=0$

List of $x$ and $y$
$x-3-2-1012$
$y046640$
$(x,y)=(-3,0),(-2,4),\left(\right(-1,6),(0,6),(1,4),(2,0).$
$\therefore$ graph $6-x-x^2$ cuts $X-$ axis at the points $-3$ and $-2$
$\therefore$ The zeroes of quadratic polynomial are $-3$ and $2.$