Draw the graphs of the equations $3 x - 2 y + 6 = 0$ and $x + 2 y - 6 = 0$ in the same graph paper. Find the area of triangle formed by two lines and $x - a x i s .$

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Solution

Area of shaded triangle $= \frac{1}{2} \times B a s e \times H e i g h t$
$= \frac{1}{2} \times (6 + 2) \times 3$
$= 4 \times 3$
$= 12 s q . u n i t s$

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Draw the graphs of the equations 3x−2y+6=0 and x+2y−6=0 in the same graph paper. Find the area of triangle formed by two lines and x−axis.

Area of shaded triangle =12×Base×Height=12×(6+2)×3=4×3=12sq.units

Draw the graphs of the equations $3 x - 2 y + 6 = 0$ and $x + 2 y - 6 = 0$ in the same graph paper. Find the area of triangle formed by two lines and $x - a x i s .$

Area of shaded triangle $= \frac{1}{2} \times B a s e \times H e i g h t$
$= \frac{1}{2} \times (6 + 2) \times 3$
$= 4 \times 3$
$= 12 s q . u n i t s$