Graphical Method of Finding Solution of a Pair of Linear Equations
Question 3 Dr...
Question
Question 3 Draw the graphs of the equations x = 3, x = 5 and 2x – y – 4 = 0. Also find the area of the quadrilateral formed by the lines and the X – axis
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Solution
X02Y=2x−4−40PointsPQ Draw the points P (0, - 4) and Q (2, 0) and joint these points and form a line PQ also draw the lines x = 3 and x = 5 ∴ Area of quadrilateral ABCD =12× distance between parallel lines (AB)×(AD+BC) [since, Quadrilateral ABCD is a trapezium] =12×2×(6+2)[∴AB=OB−OA=5−3=2,AD=2andBC=6] = 8 sq units Hence, the required area of the quadrilateral formed by the lines and the X – axis is 8 sq units