MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Area of a Triangle Given Its Vertices

Draw the grap...

Question

Draw the graphs of x + y + 3 = 0 and 3x - 2y + 4 = 0. Plot only three points per line.

Open in App

Solution

$x + y + 3 = 0$
then
$y = - 3 - x$
x -1 0 1
y -2 -3 -4

$3 x - 2 y + 4 = 0$
then
$x = \frac{2 y - 4}{3}$
x -1 2 5
y -2 0 2
The point of intersection is (-1, -2)

Suggest Corrections

thumbs-up

0

Similar questions

Q. Use graph paper for this question. Take

2 c m = 1 u n i t

on both the axes.
Draw the graphs of

x + y + 3 = 0

3 x - 2 y + 4 = 0

. Plot only three points per line.

Q. Use graph paper for this question. Take 2 cm=1 unit on both the axes,
(i) Draw the graphs of x+y+3=0 and 3x-2y+4=0. Plot only three points per line.
(ii) Write down the co-ordinates of the point of intersection of the lines.
(iii) Measure and record the distance of the point of intersection of the lines from the origin in cm.

Draw the graphs of the equations 3x – 2y = 4 and x + y – 3 = 0. On the same graph paper, find the coordinates of the point were the two graph lines intersect.

Q. Use graph paper for this question. Take

2 c m = 2

x

1 c m = 1

y

Solve graphically the following equations:

3 x + 5 y = 12; 3 x - 5 y + 18 = 0

(Plot only three points per line)

Q. Find the equation of the straight line passing through the point of intersection of the lines

3 x - y + 9 = 0

x + 2 y = 4

and the point of intersection of the lines

2 x + y - 4 = 0

x - 2 y + 3 = 0

.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Area from Coordinates

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Area of a Triangle Given Its Vertices

Standard X Mathematics

Join BYJU'S Learning Program

CrossIcon