Question

Draw the molecular orbital diagram of $N_2$, $N_2^{+}$ $N_2^{-}$. Write their electronic configuration, find the bond order and predict their magnetic behaviour. Arrange the above in increasing order of bond length.

Answer 1

Bond order $=\frac{1}{2}[N_b-N_a]$

$N_b=$ number of bonding electrons

$N_a=$ number of anti-bonding electrons

$\to$ Bond order of $N_2$ is $3$

$\to$ Bond order of $N_2^{-}$ is $2.5$

$\to$ Bond order of $N_2^{+}$ is $2.5$

Bond order $\alpha$ stability $\alpha \frac{1}{bondlength}$

order of bond length

Ans :- $N_2^{+}=N_2^{-}>N_2$