Draw the pressure-temperature and volume-temperature diagrams for an isobaric process of expansion, corresponding to n moles of an ideal gas at a pressure P0, from V0 to 2V0.
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Solution
From the equation state for an ideal gas PV=nRT, We have V=(nRP0)T or VαT At V=V0, we get T1=P0V0nR And at V=2V0, we get T2=2P0V0nR For the graph of P versus T the variation is a straight line normal to the pressure axis, the temperature varies from T1 to T2 as shown in the figure. For the graph of V versus T, the equation V=(nRP0)T or V=kT shows that the volume varies directly with the temperature (Charlie's law). So, the graph is a straight line inclined to the (V-T) axes, and passes through the origin (when produced) as shown in figure.