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Sigma Bond and Pi Bond

Draw the stru...

Question

Draw the structure of following compound.

$N a [B_{4} O_{5} (O H)_{4}] .8 H_{2} O$

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Solution

$N a [B_{4} O_{5} (O H)_{4}] .8 H_{2} O$ (Borax)

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[B_{3} O_{3} (O H)_{4}]^{-}

Q. Borax is actually made of two tetrahera and two triangular units joined together and should be written as:

N a_{2} [B_{4} O_{5} (O H)_{4}] .8 H_{2} O

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