Draw the structure of S - cis and S - trans form of 1, 3 - butadiene.

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Solution

$C H_{2} = C H - C H = C H_{2}$
This molecule can exist in two forms.
Though these two forms do not differ very much in their energy and stability, the (I) form, which is similar to 'trains' is more stable than (II) form which is similar to 'cis'. These two forms do not arise out of the hindrance to rotation about C = C, instead the restricted rotation about C-C. In order to indicate that, this cis-trans isomerism is due to restricted rotation about C-C bond, they are named as

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