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VSEPR Theory

Draw the stru...

Question

Draw the structures of the following $X e F_{4}$ .

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Solution

The structure of $X e F_{4}$ is shown below. The central Xe atom has 2 lone pairs and 4 bond pairs of electrons. The electron pair geometry is octahedral and molecular geometry is square planar. Xe atom undergoes $s p^{3} d^{2}$ hybridisation.

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Q. (a) Draw structure of the following compounds:
(i)

X e F_{4}

N_{2} O_{5}

(b) Write the structural difference between white phosphorus and red phosphorus.

Q. (a) Complete the following chemical equations:
(i)

N a O H (h o t a n d c o n c .) + C l_{2} \to

X_{e} F_{4} + O_{2} F_{2} \to

(b) Draw the structures of the following molecules :
(i)

H_{3} P O_{2}

H_{2} S_{2} O_{7}

X e O F_{4}

Q. Write the structure of the following :
i)

B r F_{3}

X e F_{4}

Q. (a) Give reasons for the following.
(i) Bond enthalpy of

F_{2}

is lower than that of

C l_{2}

P H_{3}

has lower boiling point than

N H_{3}

.
(b) Draw the structures of the following molecules.
(i)

B r F_{3}

(H P O_{3})_{3}

X e F_{4}

Q. (a) Account for the following :
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N_{2}

is less reactive at room temperature.
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N H_{3}

B i H_{3}

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(b) Draw the structures of the following :

(i) H_{4} P_{2} O_{7}

(Pyrophosphoric acid)

(i i) X e F_{4}

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