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Standard XIII

Physics

Drift Velocity

Drift speed o...

Question

Drift speed of electron, when 1.5 A of current flows in a copper wire of cross section $5 m m^{2} i s v$ . If the electron density in copper $9 \times 10^{28} / m^{3}$ the value of $v i n m m / s$ is close to (Take charge of electron to be $= 1.6 \times 10^{- 19} C$ )

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Solution

The correct option is C 0.02
Calculation of drift velocity:

Given, $i = 1.5 A, n = 9 \times^{28} / m^{3}$

$e = 1.6 \times 10^{- 19} C$ drift velocity $= v_{d}, A = 5 m m^{2}$

The current in relation with drift velocity is given by

$l = n e A v_{d}$

$v_{d} = \frac{i}{n e A}$

$= \frac{15}{9 \times 10^{28} \times 1.6 \times 10^{- 19} \times 5 \times 10^{- 6}}$

$= 0.02 m m / s$

Hence, option (D) is correct.

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Drift Velocity

Standard XIII Physics

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Drift speed of electron, when 1.5 A of current flows in a copper wire of cross section 5 mm2 is v. If the electron density in copper 9×1028/m3 the value of v in mm/s is close to (Take charge of electron to be =1.6×10−19C)

The correct option is C 0.02Calculation of drift velocity: Given, i=1.5A,n=9×28/m3 e=1.6×10−19C drift velocity =vd,A=5 mm2 The current in relation with drift velocity is given by l=neAvd vd=ineA =159×1028×1.6×10−19×5×10−6 =0.02 mm/s Hence, option (D) is correct.

Drift speed of electron, when 1.5 A of current flows in a copper wire of cross section $5 m m^{2} i s v$ . If the electron density in copper $9 \times 10^{28} / m^{3}$ the value of $v i n m m / s$ is close to (Take charge of electron to be $= 1.6 \times 10^{- 19} C$ )