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Standard XII

Physics

Drift Velocity

Drift speed o...

Question

Drift speed of electrons, when $1.5 A$ of current flows in a copper wire of cross section $5 m m 2$ , is $v$ . If the electron density in copper is $9 \times 10^{28} / m^{3}$ the value of $v$ in $m m / s$ is close to (Take charge of electron to be $= 1.6 \times 10^{- 19} C$ )

0.2

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3

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2

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0.02

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Solution

The correct option is D $0.02$
$I = n e A v_{d}$
$\Rightarrow v_{d} = \frac{I}{n e A} = \frac{1.5}{9 \times 10^{28} \times 1.6 \times 10^{- 19} \times 5 \times 10^{- 6}}$
$= 0.02 m m / s$

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(Take charge of electron to be = 1.6 \times 10^{- 19} C

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Drift speed of electrons, when 1.5A of current flows in a copper wire of cross section 5mm2, is v. If the electron density in copper is 9×1028/m3 the value of v in mm/s is close to (Take charge of electron to be =1.6×10−19C)

The correct option is D 0.02I=neAvd⇒vd=IneA=1.59×1028×1.6×10−19×5×10−6=0.02mm/s

Drift speed of electrons, when $1.5 A$ of current flows in a copper wire of cross section $5 m m 2$ , is $v$ . If the electron density in copper is $9 \times 10^{28} / m^{3}$ the value of $v$ in $m m / s$ is close to (Take charge of electron to be $= 1.6 \times 10^{- 19} C$ )

The correct option is D $0.02$
$I = n e A v_{d}$
$\Rightarrow v_{d} = \frac{I}{n e A} = \frac{1.5}{9 \times 10^{28} \times 1.6 \times 10^{- 19} \times 5 \times 10^{- 6}}$
$= 0.02 m m / s$