wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Drive an expression for Electric field due to an Electric dipole at a point on the axial line.

Open in App
Solution

Let the electric field at an axial point P at an distance r from the center of the dipole be Ep.
Electric field at P, Ep=EqEq
Or Ep=kq(ra)2kq(r+a)2 where k=14πϵo
Or Ep=kq[1(ra)21(r+a)2]
Or Ep=kq[(r+a)2(ra)2(r+a)2(ra)2]
Or Ep=kq[4ar(r2a2)2]
Or Ep=2kPr(r2a2)2 where P=2qa
For r>>a, we can neglect a2 compared to r2.
We get Ep=2kPrr4
Ep=2kPr3

657586_623390_ans_73c4f9a37708463583c19208628849ae.png

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Field and Potential Due to a Dipole
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon