CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

drolysis of an ester was carriee out seperately with 0.05 M HCl an0.05M H2SO4. Then the ratio of khcl by kh2so4


Solution

The hydrolysis of ester in the presence of acid can be treated as pseudo first order reaction
But actually it is of third order and a concentration of ester, water and acid will affect the rate of reaction.
So Rate= k[H+][H2O][Ester]
But in our experiments concentration of H2O is taken in huge excess and assumed as constant, similarly concentration of H+ in a particular experiment will not change so it is also kept as constant.
So we are writing Rate= K[ester].  {Here K=[H+][H2O]}
When we are changing the concentration of acid in two different experiments
K1 HCl/K2 H2SO4 = 0.05 [H2O]/0.1[H2O] = 1/2
 

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
QuestionImage
QuestionImage
View More...


People also searched for
QuestionImage
QuestionImage
View More...



footer-image