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Question

Dry air is slowly passed through three solutions of different concentrations, C1, C2 and C3 each containing (non-volatile) NaCl as solute and water as solvent, as shown in the fig. If the vessel 2 gains weight and the vessel 3 loses weight, then


A

C1 > C2

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B

C1 < C2

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C

C1 < C3

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D

C2 > C3

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Solution

The correct options are
B

C1 < C2


D

C2 > C3


Gain/loss in weight should be proportional to vapour pressure above that solution.

As the concentration of the non-volatile solute increases, the vapor pressure of the solvent decreases.
Since vessel 2 gained weight, this means that air carried in more vapor into vessel 2 from vessel 1 than vessel 2 carried out. This is possible only if the vapor pressure of 1 > 2, i.e. concentration in 1 is lower than that of 2.

C1 <. C2

Moving on to the next statement, vessel 3 loses weight. This is possible if the mass of the vapors coming in is lower than the mass of the vapors going out, which means that concentration of 3 is lower than that of 2.

C2 > C3


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