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Question

Dry air was passed through bulbs containing a solution of 40 g of non-volatile electrolytic solute in 360 g of water, then through bulbs containing pure water at the same temperature and finally through a tube in which pumice moistened with strong H2SO4 was kept. The water bulbs lost 0.0870 g and the sulphuric acid tube gained 2.175 g. Calculate the molar mass of solute (in gram)

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Solution

By using the formula,
PPSP=xsolute
x=Mole fraction of solute=Number of moles of soluteTotal number of moles

Substituting the values, we get
0.0872.175=40M40M+36018
25=1+M2
M=48 g

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